Geometric discrepancy theory is a sub-field of discrepancy theory, that deals with balancing points in geometric sets, such as intervals or rectangles. Two closely-related research questions in this field are:
In the simplest geometric discrepancy setting, the set of objects is the set of all sub-intervals of the real interval [0,1]. In this setting, it is possible to attain discrepancy 1: simply color the points alternately black - white - black - white - etc. Then, the discrepancy of every interval is either 0 or 1.
The problem becomes more challenging when the points are not available in advance, but arrive one by one, and each point should be colored immediately when it arrives. This setting is called the "Online Interval Discrepancy". Jiang, Kulkarni and Singla prove that:: Sec.3.2
Their proof uses a reduction to the problem of Online Tree Balancing, which is a problem of discrepancy in which the set of objects is the set of sub-trees of a complete m-ary tree with height h. For this problem, they prove that, if for a sufficiently large constant C, and m ≥ 100, then there is an online algorithm that attains discrepancy .: Sec.2
Tusnady asked what is the discrepancy when the set of objects is the set of axes-parallel rectangles contained in the unit square.
When the set of objects is the set of all rectangles (possibly rotated), then:
Matousek studied the d-dimensional extension of Tusnady's problem. Improving previous results by Roth, Schmidt, Beck, Bohus, and Srinivasan, he proved an upper bound of with a simple proof.
When the set of objects is the set of stripes—rectangles of the form [a,b]x[0,1] and [0,1]x[a,b], the setting is equivalent to the problem of "two permutations": given two permutations on a set of n elements, we should color each element either black or white, such that the discrepancy in each interval of each permutation is minimized (the two permutations are the order of the x coordinates and the order of the y coordinates of the points).
Jiang, Kulkarni and Singla study the online setting with stochastic point arrival, and prove that:
Matousek and Nikolov studied a more general setting, where the set of objects is induced by dilations and translations of a fixed convex polytope. He proved upper and lower bounds on the discrepancy. The results are analogous to the results for rectangles and boxes.
When the set of objects is the set of half-spaces in the Euclidean d-dimensional space:
In expected-value (Lebesgue-measure) discrepancy, a set P of N points in the unit cube is compared with the uniform distribution instead of being colored. For a point of the cube, the discrepancy function of P is
where is the box anchored at the origin and is its volume. A well-distributed point set is one for which is small in some function norm, and the central lower-bound question asks how small these norms can be, uniformly over all N-point sets.: Sec. 1 Most of the classical bounds were obtained by variants of a single approach, due to Roth, based on expanding in Haar or other orthogonal functions.
Roth proved that every N-point set in satisfies
where is a constant that depends only on the dimension.: Thm. 1 Schmidt later showed that the same lower bound holds for the norm for every .: Sec. 1
Roth's argument, now called the orthogonal function method, works with the multiparameter Haar basis.: Sec. 2 A dyadic rectangle is a product of dyadic intervals, and its Haar function is the product of the one-dimensional Haar functions of its sides. One fixes an integer n with , so that , and considers only the dyadic rectangles of volume . For each of the roughly possible shapes of such rectangles, there are rectangles of that shape, so at least half of them contain no point of P. On an empty rectangle, the counting part of is orthogonal to , so the Haar coefficient comes from the volume term alone and has a known sign and size. Summing, with matching signs, the Haar functions of the empty rectangles of one shape gives a function whose pairing with is bounded below by a constant; functions belonging to different shapes are orthogonal. Their sum F therefore satisfies while , and the Cauchy–Schwarz inequality gives Roth's bound.: Sec. 2
Roth's bound is not sharp for the supremum norm. In two dimensions, Schmidt proved that , which is larger than the bound by a factor of and is attained, up to the constant, by the van der Corput point set.: Sec. 1
Halász refined Roth's method by replacing the linear test function F with a Riesz product built from the same functions . In two dimensions the shapes of rectangles of area are for , and the Haar functions obey a product rule: the product of the Haar functions of two such rectangles with different shapes is, up to sign, the Haar function of a smaller rectangle. As a result, the functions behave like independent random signs, a product such as is non-negative with integral 1, and its expansion consists of Roth's linear term plus higher-order terms whose pairings with are small.: Sec. 5 This yields a new proof of Schmidt's bound.: Sec. 5
Using a bounded Riesz product of this kind as a dual test function, Halász also proved that in two dimensions
so Roth's bound already holds for the norm.: Sec. 1 His argument gives only in dimensions , and whether Roth's bound holds for the norm in those dimensions is a well-known conjecture. The main obstacle in higher dimensions is that the product rule fails when two dyadic rectangles of the same volume share a side length.: Sec. 6
Let be a family of measurable subsets of the unit cube .
In the first problem one chooses the best placement of the points; in the second the points are given by an adversary and one chooses only the coloring.: Sec. 1
The transference principle (or transference lemma) states that small combinatorial discrepancy implies small Lebesgue-measure discrepancy. Suppose that contains the whole cube, that , and that for a function f satisfying for some fixed . Then .: Thm. 3 The idea is attributed to Sós, and Beck used it in his lower bound for Tusnády's problem.: Sec. 1 A general form of the principle was given by Lovász, Spencer and Vesztergombi,: Sec. 2.3 who also proved the closely related inequality that the linear discrepancy of a set system (the worst case of rounding fractional weights to 0 and 1) is at most twice its hereditary discrepancy.
The proof is by repeated halving. One starts from a very large point set whose Lebesgue-measure discrepancy is small relative to its size, which exists by the assumption . If P has points and is a coloring of P with discrepancy at most , then, for one color class ,
for every , so . Because the whole cube belongs to , the two color classes have almost equal sizes. Repeating the step until N points remain, the errors form a geometric series, and the growth condition on f makes the sum .: Sec. 2.3
The same argument works when Lebesgue measure is replaced by an arbitrary Borel probability measure on the cube, with a constant that does not depend on the measure.: Sec. 2.3
The relation cannot be reversed in general. For the family of all convex subsets of the unit cube, the Lebesgue-measure discrepancy is of order , while the combinatorial discrepancy is of order N.: Sec. 2.3 The combinatorial value is large because the adversary may place the points on a sphere, where every subset of the points is cut out by a convex set, namely its own convex hull. Likewise, lower bounds for Tusnády's problem do not imply lower bounds for the Lebesgue-measure problem, since the combinatorial problem requires the chosen points to come from a given point set.: Sec. 2.2